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KCET · Maths · Trigonometric Ratios & Identities

\(3(\sin x-\cos x)^{4}+6(\sin x+\cos x)^{2}\)
\(+4\left(\sin ^{6} x+\cos ^{6} x\right)\)
is equal to

  1. A 12
  2. B 13
  3. C 14
  4. D 11
Verified Solution

Answer & Solution

Correct Answer

(B) 13

Step-by-step Solution

Detailed explanation

\(3(\sin x-\cos x)^{4}+6(\sin x+\cos x)^{2}\)
\(+4\left(\sin ^{6} x+\cos ^{6} x\right)\)
\(=3(1-2 \sin x \cos x)^{2}+6(1+2 \sin x \cos x)\)
\(\quad+4\left(\sin ^{2} x+\cos ^{2} x\right)\left(\sin ^{4} x+\cos ^{4} x\right.\)
\(\left.\quad-\sin ^{2} x \cos ^{2} x\right)\)
\(=3\left[1+4 \sin ^{2} x \cos ^{2} x-4 \sin x \cos x\right]\)
\(\quad+6+12 \sin x \cos x+4\left[\left(\sin ^{2} x+\cos ^{2} x\right)^{2}\right.\)
\(\left.\quad-2 \sin ^{2} x \cos ^{2} x-\sin ^{2} x \cos ^{2} x\right]\)