KCET · Chemistry · States of Matter
The rms velocity of molecules of a gas of density \(4 \mathrm{~kg} \mathrm{~m}^{-3}\) and pressure \(1.2 \times 10^{5} \mathrm{Nm}^{-2}\) is
- A \(300 \mathrm{~ms}^{-1}\)
- B \(900 \mathrm{~ms}^{-1}\)
- C \(120 \mathrm{~ms}^{-1}\)
- D \(600 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(300 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{v}_{\mathrm{rms}} &=\sqrt{\frac{3 \mathrm{p}}{\mathrm{d}}} \\ &=\sqrt{\frac{3 \times 1.2 \times 10^{5}}{4}}=300 \mathrm{~ms}^{-1} \end{aligned}\)
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