KCET · Chemistry · General Organic Chemistry
Angle strain in cyclopropane is
- A \(24^{\circ} 44^{\prime}\)
- B \(9^{\circ} 44^{\prime}\)
- C \(44^{\prime}\)
- D \(-5^{\circ} 16^{\prime}\)
Answer & Solution
Correct Answer
(A) \(24^{\circ} 44^{\prime}\)
Step-by-step Solution
Detailed explanation
Angle strain in cyclopropane is \(24^{\circ} 44^{\prime}\)
\[
\begin{aligned}
\theta &=\left[180-\frac{360}{n}\right] \\
&=\left[180-\frac{360}{3}\right]=180-120=60^{\circ}
\end{aligned}
\]
\[
\text { Angle strain } \begin{aligned}
\alpha &=\frac{1}{2}\left[109^{\circ} 28^{\circ}-\theta\right] \\
&=\frac{1}{2}\left[109^{\circ} 28^{\prime}-60^{\circ}\right] \\
&=24^{\circ} 44^{\prime}
\end{aligned}
\]
\[
\begin{aligned}
\theta &=\left[180-\frac{360}{n}\right] \\
&=\left[180-\frac{360}{3}\right]=180-120=60^{\circ}
\end{aligned}
\]
\[
\text { Angle strain } \begin{aligned}
\alpha &=\frac{1}{2}\left[109^{\circ} 28^{\circ}-\theta\right] \\
&=\frac{1}{2}\left[109^{\circ} 28^{\prime}-60^{\circ}\right] \\
&=24^{\circ} 44^{\prime}
\end{aligned}
\]
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