KCET · Chemistry · Amines
Density of carbon monoxide is maximum at
- A \( 0.5 \mathrm{~atm} \) and \( 273 \mathrm{~K} \)
- B \( 4 \mathrm{~atm} \) and \( 500 \mathrm{~K} \)
- C \( 2 \mathrm{~atm} \) and \( 600 \mathrm{~K} \)
- D \( 6 \mathrm{~atm} \) and \( 1092 \mathrm{~K} \)
Answer & Solution
Correct Answer
(B) \( 4 \mathrm{~atm} \) and \( 500 \mathrm{~K} \)
Step-by-step Solution
Detailed explanation
From ideal gas equation \( \rho=\frac{p M}{R T} \rightarrow(1) \)
In Eq. (1), R and M is constant for a gas.
Therefore, \( \rho \propto \frac{p}{T} \)
\(\begin{array}{|l|l|l|}
\hline Pressure(p) in atm & Temperature (T) in K & Density, \boldsymbol{\rho} \boldsymbol{\alpha} \frac{\boldsymbol{p}}{\boldsymbol{T}} \\
\hline 0.5 & 273 & \frac{0.5}{273}=0.0018 \\
\hline 4 & 500 & \frac{4}{500}=0.008 \\
\hline 2 & 600 & \frac{2}{600}=0.0033 \\
\hline 6 & 1092 & \frac{6}{1092}=0.0055 \\
\hline
\end{array}\)
The \( \mathrm{p} / \mathrm{T} \) ratio is highest at \( 4 \mathrm{~atm} \) and \( 500 \mathrm{~K} \).
Therefore, density of carbon monoxide is maximum at \( 4 \mathrm{~atm} \) and \( 500 \mathrm{~K} \).
In Eq. (1), R and M is constant for a gas.
Therefore, \( \rho \propto \frac{p}{T} \)
\(\begin{array}{|l|l|l|}
\hline Pressure(p) in atm & Temperature (T) in K & Density, \boldsymbol{\rho} \boldsymbol{\alpha} \frac{\boldsymbol{p}}{\boldsymbol{T}} \\
\hline 0.5 & 273 & \frac{0.5}{273}=0.0018 \\
\hline 4 & 500 & \frac{4}{500}=0.008 \\
\hline 2 & 600 & \frac{2}{600}=0.0033 \\
\hline 6 & 1092 & \frac{6}{1092}=0.0055 \\
\hline
\end{array}\)
The \( \mathrm{p} / \mathrm{T} \) ratio is highest at \( 4 \mathrm{~atm} \) and \( 500 \mathrm{~K} \).
Therefore, density of carbon monoxide is maximum at \( 4 \mathrm{~atm} \) and \( 500 \mathrm{~K} \).
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