KCET · Chemistry · Thermodynamics (C)
A gas expands from a volume of \(1 \mathrm{~m}^{3}\) to a volume of \(2 \mathrm{~m}^{3}\) against an external pressure of \(10^{5} \mathrm{Nm}^{-2}\). The work done by the gas will be
- A \(10^{2} \mathrm{~kJ}\)
- B \(10^{2} \mathrm{~J}\)
- C \(10^{3} \mathrm{~J}\)
- D \(10^{5} \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(A) \(10^{2} \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{W}=\mathrm{p} \Delta \mathrm{V}\)
\(=10^{5}(2-1)=10^{5} \mathrm{~J}=10^{2} \mathrm{~kJ}\)
\(=10^{5}(2-1)=10^{5} \mathrm{~J}=10^{2} \mathrm{~kJ}\)
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