KCET · Chemistry · Chemical Kinetics
\( 3 \mathrm{~A} \rightarrow 2 \mathrm{~B} \), rate of reaction \( +\frac{d[B]}{d t} \) is equal to
- A \( -\frac{3 d[A]}{2 d t} \)
- B \( -\frac{2}{3} d[A] \)
- C \( +2 \frac{d[A]}{d t} \)
- D \( -\frac{1}{3} \frac{d[A]}{d t} \)
Answer & Solution
Correct Answer
(B) \( -\frac{2}{3} d[A] \)
Step-by-step Solution
Detailed explanation
For reaction, \(3 \mathrm{~A} \rightarrow 2 \mathrm{~B}\)
Rate of appearance \(=\) Rate of disappearance.
\(+\frac{1}{2} \frac{d[B]}{d t}=-\frac{1}{3} \frac{d[A]}{d t}\)
\(\frac{d[B]}{d t}=-\frac{2}{3} \frac{d[A]}{d t}\)
Rate of appearance \(=\) Rate of disappearance.
\(+\frac{1}{2} \frac{d[B]}{d t}=-\frac{1}{3} \frac{d[A]}{d t}\)
\(\frac{d[B]}{d t}=-\frac{2}{3} \frac{d[A]}{d t}\)
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