KCET · Chemistry · Coordination Compounds
\( \mathrm{CO} \) is a stronger ligand than \( \mathrm{Cl}^{-} \), because
- A \( \mathrm{CO} \) is a neutral molecule.
- B CO has \( \pi \)-bonds.
- C \( \mathrm{CO} \) is poisonous.
- D \( \mathrm{CO} \) is more reactive.
Answer & Solution
Correct Answer
(B) CO has \( \pi \)-bonds.
Step-by-step Solution
Detailed explanation
\( \mathrm{CO} \) is a stronger ligand than \( \mathrm{Cl}^{-} \)because, \( \mathrm{CO} \) is a \( \mathrm{II} \) - acceptor ligand due to multiple bonds in \( \mathrm{CO} \) and vacant
antibonding orbital of \( \mathrm{C} \) atom in \( \mathrm{CO} \).
antibonding orbital of \( \mathrm{C} \) atom in \( \mathrm{CO} \).
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