KCET · Chemistry · Chemical Bonding and Molecular Structure
In oxygen and carbon molecule the bonding is
- A \(\mathrm{O}_2: 2 \sigma, 0 \pi ; \mathrm{C}_2: 0 \sigma, 2 \pi\)
- B \(\mathrm{O}_2: 1 \sigma, 1 \pi ; \mathrm{C}_2: 0 \sigma, 2 \pi\)
- C \(\mathrm{O}_2: 0 \sigma, 2 \pi ; \mathrm{C}_2: 2 \sigma, 0 \pi\)
- D \(\mathrm{O}_2: 1 \sigma, 1 \pi ; \mathrm{C}_2: 1 \sigma, 1 \pi\)
Answer & Solution
Correct Answer
(B) \(\mathrm{O}_2: 1 \sigma, 1 \pi ; \mathrm{C}_2: 0 \sigma, 2 \pi\)
Step-by-step Solution
Detailed explanation
The bond order of \(\mathrm{C}_2\) consists of both pi bond because of the presence of the four electrons in two pi molecular orbitals. Whereas in most of the other molecules a double bond is made up of a sigma bond and a pi bond.
Thus, option (b) is correct.
Thus, option (b) is correct.
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