KCET · Chemistry · Haloalkanes and Haloarenes
In the given sequence of reactions, identify \({ }^{\prime} P^{\prime}, ' Q{ }^{\prime}, R^{\prime}\) and ' \(S\) respectively.
\(\mathrm{CH}_2= \underset{\underset{}{\Large | ~~~~} \atop \huge \mathrm{Br}}{\mathrm{CH}_2}-\underset{\underset{}{\Large | ~~~~} \atop \huge \mathrm{Br}}{\mathrm{CH}_2} \xrightarrow{Q}\)
\(\mathrm{CH}_2=\mathrm{CH}-\mathrm{Br} \xrightarrow{R} \mathrm{CH} \equiv \mathrm{CH} \xrightarrow{s} \mathrm{C}_6 \mathrm{H}_6\)
- A \(\mathrm{Br}_2\), Alc. \(\mathrm{KOH}, \mathrm{NaOH}, \mathrm{Al}_2 \mathrm{O}_3\)
- B \(\mathrm{HBr}, \mathrm{Alc} . \mathrm{KOH}, \mathrm{CaC}_2, \mathrm{KMnO}_4\)
- C HBr , Alc. \(\mathrm{KOH}, \mathrm{NaNH}_2\), Red hot iron tube
- D \(\mathrm{Br}_2\), Alc. \(\mathrm{KOH}, \mathrm{NaNH}_2\), Red hot iron tube
Answer & Solution
Correct Answer
(D) \(\mathrm{Br}_2\), Alc. \(\mathrm{KOH}, \mathrm{NaNH}_2\), Red hot iron tube
Step-by-step Solution
Detailed explanation
The complete reaction sequence involved is as follows
Thus, the reagent \(P, Q, R\) and \(S\) are \(\mathrm{Br}_2\), alc. KOH, \(\mathrm{NaNH}_2\), Red hot iron respectively.
Thus, the reagent \(P, Q, R\) and \(S\) are \(\mathrm{Br}_2\), alc. KOH, \(\mathrm{NaNH}_2\), Red hot iron respectively.
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