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JEE Mains · Physics · STD 11 - 13. oscillations
Two simple harmonic motions, as shown, are at right angles. They are combined to form Lissajous figures \(x\left( t \right) = A\,\sin \,\left( {at + \delta } \right)\) \(y\left( t \right) = B\,\sin \,\left( {bt} \right)\) Identify the correct match below
- A Parameters: \(A\, = B\), \(a\, = 2b\); \(\delta = \frac{\pi }{2}\); Curve : Circle
- B Parameters: \(A\,= B\), \(a\, = b\); \(\delta = \frac{\pi }{2}\) ; Curve : Line
- C Parameters: \(A \ne B\), \(a\, = b\); \(\delta = \frac{\pi }{2}\); Curve : Ellipse
- D Parameters: \(A \ne B\), \(a\, = b\); \(\delta\, = 0\); Curve : Parabola
Answer & Solution
Correct Answer
(C) Parameters: \(A \ne B\), \(a\, = b\); \(\delta = \frac{\pi }{2}\); Curve : Ellipse
Step-by-step Solution
Detailed explanation
From the two mutually perpendicular \(S.H.M. 's\), the general equation of Lissajous figure \(\frac{{{x^2}}}{{{A^2}}} + \frac{{{y^2}}}{{{B^2}}} - \frac{{2xy}}{{AB}}\cos \,\delta = {\sin ^2}\,\delta\) \(x = A\,\sin \,\left( {at + \delta } \right)\)…
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