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JEE Mains · Physics · STD 12 - 3. current electricity
A letter \('A'\) is constructed of a uniform wire with resistance \(1.0\,\Omega \) per \(cm\) , The sides of the letter are \(20\, cm\) and the cross piece in the middle is \(10\, cm\) long. The apex angle is \(60\) . The resistance between the ends of the legs is close to ................ \(\Omega\)
- A \(50\)
- B \(10\)
- C \(36.7\)
- D \(26.7\)
Answer & Solution
Correct Answer
(D) \(26.7\)
Step-by-step Solution
Detailed explanation
For \(ADE\) \(\frac{1}{\mathrm{R}^{\prime}}=\frac{1}{2 \mathrm{x}}+\frac{1}{10}\) or \(\quad \mathrm{R}^{\prime}=\frac{20 \mathrm{x}}{10+2 \mathrm{x}}\) \(\mathrm{R}_{\mathrm{BC}}=\frac{20 \mathrm{x}}{10+2 \mathrm{x}}+20-\mathrm{x}+20-\mathrm{x}\) ....\((i)\) or…
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