JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2021
- Hard
- Numerical
Two circuit are shown in the figure \((a)\) and \((b).\) At a frequency of \(....\,rad/s\) the average power dissipated in one cycle will be same in both the circuits.

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(500\)
Step-by-step Solution
Detailed explanation
\(P_{\text {avg }}=\frac{v_{\text {rms }}^{2}}{R}\)
\(\frac{v_{ rms }^{2}}{Z^{2}} \times R=\frac{v_{r m s}^{2}}{R} \times 1\)
\(R^{2}=Z^{2}\)
\(25=\left(\sqrt{\left(x_{C}-x_{L}\right)^{2}+5^{2}}\right)^{2}\)
\(25=\left(x_{c}-x_{L}\right)^{2}+25\)
\(x_{c}=x_{L} \Rightarrow \frac{1}{\omega C}=\omega L\)
\(\omega^{2}=\frac{1}{L C}=\frac{10^{6}}{0.1 \times 40}\)
\(\omega=500\)
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