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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2021
  • Hard
  • Numerical

Two circuit are shown in the figure \((a)\) and \((b).\) At a frequency of \(....\,rad/s\) the average power dissipated in one cycle will be same in both the circuits.

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Answer & Solution

Correct Answer

(C) \(500\)

Step-by-step Solution

Detailed explanation

\(P_{\text {avg }}=\frac{v_{\text {rms }}^{2}}{R}\)

\(\frac{v_{ rms }^{2}}{Z^{2}} \times R=\frac{v_{r m s}^{2}}{R} \times 1\)

\(R^{2}=Z^{2}\)

\(25=\left(\sqrt{\left(x_{C}-x_{L}\right)^{2}+5^{2}}\right)^{2}\)

\(25=\left(x_{c}-x_{L}\right)^{2}+25\)

\(x_{c}=x_{L} \Rightarrow \frac{1}{\omega C}=\omega L\)

\(\omega^{2}=\frac{1}{L C}=\frac{10^{6}}{0.1 \times 40}\)

\(\omega=500\)

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