JEE Mains · Physics · STD 12 - 1. Electric charges and fields
A uniform electric field of \(10\,N / C\) is created between two parallel charged plates (as shown in figure). An electron enters the field symmetrically between the plates with a kinetic energy \(0.5\,eV\). The length of each plate is \(10\,cm\). The angle \((\theta)\) of deviation of the path of electron as it comes out of the field is \(.........\)(in degree).
- A \(44\)
- B \(43\)
- C \(42\)
- D \(45\)
Answer & Solution
Correct Answer
(D) \(45\)
Step-by-step Solution
Detailed explanation
\(0.5\,e =\frac{1}{2}\,mv _{ x }^2 \Rightarrow v _{ x }=\sqrt{\frac{ e }{ m }}\) Along \(x L =v_x t=\sqrt{\frac{ e }{ m }} t\) Along y \(v _{ y }=\frac{e e }{ m } t\) \(\operatorname{dividing} \frac{ v _{ y }}{ L }= E \sqrt{\frac{ e }{ m }}= Ev _{ x }\)…
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