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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2025
  • Easy
  • MCQ

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is \(I_0\). If the value of resistance R becomes twice of its initial value then amplitude of current at resonance will be :

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Answer & Solution

Correct Answer

(C) \(\frac{\mathrm{I}_0}{2}\)

Step-by-step Solution

Detailed explanation

Initially, \(\mathrm{I}_0=\frac{\varepsilon_{\mathrm{m}}}{\mathrm{R}}\)
Finally, \(\mathrm{I}_0^1=\frac{\varepsilon_{\mathrm{m}}}{2 \mathrm{R}}=\frac{\mathrm{I}_0}{2}\)
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