JEE Mains · Physics · STD 11 - 13. oscillations
In an experiment to determine the period of a simple pendulum of length \(1\, m\), it is attached to different spherical bobs of radii \(r_1\) and \(r_2\) . The two spherical bobs have uniform mass distribution. If the relative difference in the periods, is found to be \(5\times10^{-4}\, s\), the difference in radii, \(\left| {{r_1} - {r_2}} \right|\) is best given by .... \(cm\)
- A \(1\)
- B \(0.1\)
- C \(0.5\)
- D \(0.01\)
Answer & Solution
Correct Answer
(B) \(0.1\)
Step-by-step Solution
Detailed explanation
As we know, Time-period of simple pendulum, T \(\propto \sqrt{l}\) \(5 \times {10^{ - 4}} = \frac{1}{2}\frac{{{r_1} - {r_2}}}{1}\) \(\because\) change in length \(\Delta l=r_{1}-r_{2}\) \(5 \times {10^{ - 4}} = \frac{1}{2}\frac{{{r_1} - {r_2}}}{1}\)…
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