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JEE Mains · Physics · STD 11 - 9.1 fluid mechanics

A solid steel ball of diameter 3.6 mm acquired terminal velocity \(2.45 \times 10^{-2} \mathrm{~m} / \mathrm{s}\) while falling under gravity through an oil of density \(925 \mathrm{~kg} \mathrm{~m}^{-3}\). Take density of steel as \(7825 \mathrm{~kg} \mathrm{~m}^{-3}\) and g as 9.8 \(\mathrm{m} / \mathrm{s}^2\). The viscosity of the oil in SI unit is

  1. A \(2.18\)
  2. B \(2.38\)
  3. C \(1.68\)
  4. D \(1.99\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1.99\)

Step-by-step Solution

Detailed explanation

\(\mathrm{v}_{\mathrm{T}} \Rightarrow \frac{2}{9} \frac{\left(\rho_0-\rho_{\ell}\right) \mathrm{r}^2 \mathrm{~g}}{\eta}\)…