JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2025
- Hard
- MCQ
A light wave is propagating with plane wave fronts of the type \(x+y+z=\) constant. The angle made by the direction of wave propagation with the \(x\)-axis is:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
Step-by-step Solution
Detailed explanation
The direction of propagation of light is perpendicular to the wave front and is symmetric about \(\mathrm{x}, \mathrm{y}\) and z axis.
\(\therefore\) Angle made by the light with \(\mathrm{x}, \mathrm{y} \& \mathrm{z}\) axis is same.
\(\therefore \quad \cos \alpha=\cos \beta=\cos \gamma(\alpha, \beta \& \gamma\) are angle made by light with \(\mathrm{x}, \mathrm{y} \& \mathrm{z}\) axis respectively)
Also \(\cos ^2 \alpha+\cos ^2 \beta+\cos ^2 \gamma=1\) [Sum of direction cosines]
\(\therefore \alpha=\cos ^{-1} \frac{1}{\sqrt{3}}\)
\(\therefore\) Angle made by the light with \(\mathrm{x}, \mathrm{y} \& \mathrm{z}\) axis is same.
\(\therefore \quad \cos \alpha=\cos \beta=\cos \gamma(\alpha, \beta \& \gamma\) are angle made by light with \(\mathrm{x}, \mathrm{y} \& \mathrm{z}\) axis respectively)
Also \(\cos ^2 \alpha+\cos ^2 \beta+\cos ^2 \gamma=1\) [Sum of direction cosines]
\(\therefore \alpha=\cos ^{-1} \frac{1}{\sqrt{3}}\)
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