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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2020
  • Medium
  • MCQ

Two resistors \(400\, \Omega\) and \(800\, \Omega\) are connected in series across a \(6 V\) battery. The potential difference measured by a voltmeter of \(10\, k \Omega\) across \(400\, \Omega\) resistor is close to\(....V\)

Pick an option to check your answer.
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Answer & Solution

Correct Answer

(B) \(1.95\)

Step-by-step Solution

Detailed explanation

So the potential difference in voltmeter across

the points \(A\) and \(B\) is \(\frac{6}{1185} \times 385=1.949 V\)

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