JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Calculate the amount of charge on capacitor of \(4\, \mu\, {F}\). The internal resistance of battery is \(1\, \Omega\) : (in \(\mu {C}\))
- A \(8\)
- B \(1\)
- C \(16\)
- D \(14\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
On simplifying circuit we get No current in upper wire. \(\therefore \quad {V}_{{AB}}=\frac{5}{4+1} \times 4=4 {v}\) \(\therefore \quad \theta=\left({C}_{{eq}}\right) {v}\) \(\Rightarrow 2 \times 4=8 \mu {C}\)
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