JEE Mains · Physics · STD 11 - 7. gravitation
Two objects of equal masses placed at certain distance from each other attracts each other with a force of \(F\). If one-third mass of one object is transferred to the other object, then the new force will be
- A \(\frac{2}{9}F\)
- B \(\frac{16}{9}F\)
- C \(\frac{8}{9}F\)
- D \(F\)
Answer & Solution
Correct Answer
(C) \(\frac{8}{9}F\)
Step-by-step Solution
Detailed explanation
\(F =\frac{ Gm ^{2}}{ r ^{2}}\) \(F ^{\prime}=\frac{ G \left(\frac{4 m }{3}\right) \times\left(\frac{2 m }{3}\right)}{ r ^{2}}\) \(F ^{\prime}=\frac{8}{9} F\)
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