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JEE Mains · Physics · STD 11- Mechanical properties of solids
  • JEE Mains 2013
  • Hard
  • MCQ

Two blocks of masses \(m\) and \(M\) are connected by means of a metal wire of cross-sectional area \(A\) passing over a frictionless fixed pulley as shown in the figure. The system is then released. If \(M = 2\, m\), then the stress produced in the wire is

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Answer & Solution

Correct Answer

(B) \(\frac{{4mg}}{{3A}}\)

Step-by-step Solution

Detailed explanation

Tension in the wire, \(T = \left( {\frac{{2mM}}{{m + M}}} \right)g.\)

\(Stress = \frac{{Force/Tension}}{{Area}} = \frac{{2mM}}{{A\left( {m + M} \right)}}g\)

\( = \frac{{2\left( {m \times 2m} \right)g}}{{A\left( {m + 2m} \right)}}\left( {M = 2m\,given} \right)\)

\( = \frac{{4{m^2}}}{{3mA}}g = \frac{{4mg}}{{3A}}\)

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