JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A system consists of two identical spheres each of mass \(1.5\, {kg}\) and radius \(50\, {cm}\) at the end of light rod. The distance between the centres of the two spheres is \(5\, {m}\). What will be the moment of inertia of the system about an axis perpendicular to the rod passing through its midpoint ? (in \({kgm}^{2}\))
- A \(18.75\)
- B \(1.905\)
- C \(19.05\)
- D \(1.875\)
Answer & Solution
Correct Answer
(C) \(19.05\)
Step-by-step Solution
Detailed explanation
\({M}=1.5\, {kg}, {r}=0.5 \,{m}, {d}=\frac{5}{2}\, {m}\) \({I}=2\left(\frac{2}{5} {Mr}^{2}+{Md}^{2}\right)\) \(=19.05\, {kgm}^{2}\)
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