ExamBro
ExamBro
JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2021
  • Hard
  • MCQ

A system consists of two identical spheres each of mass \(1.5\, {kg}\) and radius \(50\, {cm}\) at the end of light rod. The distance between the centres of the two spheres is \(5\, {m}\). What will be the moment of inertia of the system about an axis perpendicular to the rod passing through its midpoint ? (in \({kgm}^{2}\))

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(19.05\)

Step-by-step Solution

Detailed explanation

\({M}=1.5\, {kg}, {r}=0.5 \,{m}, {d}=\frac{5}{2}\, {m}\)

\({I}=2\left(\frac{2}{5} {Mr}^{2}+{Md}^{2}\right)\)

\(=19.05\, {kgm}^{2}\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app