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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2014
  • Hard
  • MCQ

Two monochromatic light beams of intensity \(16\) and \(9\) units are interfering . The ratio of intensities of bright and dark parts of the resultant pattern is

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Answer & Solution

Correct Answer

(D) \(\frac{49}{1}\)

Step-by-step Solution

Detailed explanation

Intensity \(\propto\) (amplitude) \(^{2}\)

\(\frac{I_{1}}{I_{2}}=\frac{16}{9}=\frac{a_{1}^{2}}{a_{2}^{2}}\)

\(\Rightarrow a_{1}=4 ; a_{2}=3\)

Therefore the ratio of intensities of bright and dark parts

\(\frac{{{I_{{\text{Bright }}}}}}{{{I_{{\text{Dark }}}}}} = \frac{{{{\left( {{a_1} + {a_2}} \right)}^2}}}{{{{\left( {{a_1} - {a_2}} \right)}^2}}}\) \( = \frac{{{{(4 + 3)}^2}}}{{{{(4 - 3)}^2}}} = \frac{{49}}{1}\)

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