JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2014
- Hard
- MCQ
Two monochromatic light beams of intensity \(16\) and \(9\) units are interfering . The ratio of intensities of bright and dark parts of the resultant pattern is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\frac{49}{1}\)
Step-by-step Solution
Detailed explanation
Intensity \(\propto\) (amplitude) \(^{2}\)
\(\frac{I_{1}}{I_{2}}=\frac{16}{9}=\frac{a_{1}^{2}}{a_{2}^{2}}\)
\(\Rightarrow a_{1}=4 ; a_{2}=3\)
Therefore the ratio of intensities of bright and dark parts
\(\frac{{{I_{{\text{Bright }}}}}}{{{I_{{\text{Dark }}}}}} = \frac{{{{\left( {{a_1} + {a_2}} \right)}^2}}}{{{{\left( {{a_1} - {a_2}} \right)}^2}}}\) \( = \frac{{{{(4 + 3)}^2}}}{{{{(4 - 3)}^2}}} = \frac{{49}}{1}\)
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