JEE Mains · Maths · STD 12 - 8. Application and integration
The area of the region enclosed by the parabola \((y-2)^2=x-1\), the line \(x-2 y+4=0\) and the positive coordinate axes is
- A \(5\)
- B \(4\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
Solving the equations \((y-2)^2=x-1 \text { and } x-2 y+4=0\) \(x=2(y-2)\) \(\frac{x^2}{4}=x-1\) \(x^2-4 x+4=0\) \((x-2)^2=0 \) \(x=2 \)Exclose area (w.r.t. y-axis) \(=\int_0^3 x \mathrm{dy}-\) Area of \(\Delta\).…
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