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JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2021
- Hard
- MCQ
The angular frequency of alternating current in a \(L-C-R\) circuit is \(100\, rad / s\). The components connected are shown in the figure. Find the value of inductance of the coil and capacity of condenser.

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Answer & Solution
Correct Answer
(B) \(0.8\, H\) and \(250\, \mu F\)
Step-by-step Solution
Detailed explanation
Current through \(60 \Omega\) resistance \(=\frac{15}{60}=\frac{1}{4} A\)
thus capacitor current \(=\frac{1}{4} A\)
\(\because V _{ C }= I X _{ C }\)
\(10=\frac{1}{4} \times \frac{1}{\omega C}\)
\(\therefore C =\frac{1}{40 \omega}=\frac{1}{4000}=250 \mu F\)
Now,
current through \(40 \Omega\) resistance \(=\frac{20}{40}=\frac{1}{2} A\)
thus current through inductor \(=\frac{1}{2}-\frac{1}{4}=\frac{1}{4} A\)
\(V _{ L }= IX _{ L }=\frac{1}{4} \times \omega L\)
\(20=\frac{1}{4} \times 100 \times L\)
\(\Rightarrow L =0.8 H\)
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