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JEE Mains · Physics · STD 12 - 3. current electricity

Two cells of emfs \(1\) V and \(2\) V and internal resistance \(2\,\Omega\) and \(1\,\Omega\), respectively connected in parallel, gave a current of \(1\) A through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be \(\dfrac{\alpha}{5}\) A. The value of \(\alpha\) is __________.

  1. A 1
  2. B 2
  3. C 3
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(C) 3

Step-by-step Solution

Detailed explanation

For two cells connected in parallel with the same polarity, the equivalent emf \(E_{eq}\) and equivalent internal resistance \(r_{eq}\) are given by: \(E_{eq} = \dfrac{E_1 r_2 + E_2 r_1}{r_1 + r_2}\) \(r_{eq} = \dfrac{r_1 r_2}{r_1 + r_2}\) Substituting the given values (…
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