JEE Mains · Physics · STD 12 - 3. current electricity
Two cells of emfs \(1\) V and \(2\) V and internal resistance \(2\,\Omega\) and \(1\,\Omega\), respectively connected in parallel, gave a current of \(1\) A through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be \(\dfrac{\alpha}{5}\) A. The value of \(\alpha\) is __________.
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
For two cells connected in parallel with the same polarity, the equivalent emf \(E_{eq}\) and equivalent internal resistance \(r_{eq}\) are given by: \(E_{eq} = \dfrac{E_1 r_2 + E_2 r_1}{r_1 + r_2}\) \(r_{eq} = \dfrac{r_1 r_2}{r_1 + r_2}\) Substituting the given values (…
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