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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2025
  • Easy
  • MCQ

A balloon and its content having mass \(M\) is moving up with an acceleration ' \(a\) '. The mass that must be released from the content so that the balloon starts moving up with an acceleration ' \(3 a^{\prime}\) will be
(Take ' g ' as acceleration due to gravity)

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Answer & Solution

Correct Answer

(A) \(\frac{2 \mathrm{Ma}}{3 \mathrm{a}+\mathrm{g}}\)

Step-by-step Solution

Detailed explanation




\(\begin{aligned}
& F-m g=m a \\
& F=m a+m g \\
& F-(m-x) g=(m-x) 3 a
\end{aligned}\)

Put F
\(\begin{aligned}
& \mathrm{Ma}+\mathrm{mg}-\mathrm{mg}+\mathrm{xg}=3 \mathrm{ma}-3 \mathrm{xa} \\
& \mathrm{x}=\frac{2 \mathrm{ma}}{\mathrm{~g}+3 \mathrm{a}}
\end{aligned}\)
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