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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2013
  • Medium
  • MCQ

A current \(i\) is flowing in a straight conductor of length \(L.\) The magnetic induction at a point on its axis at a distance \(\frac {L}{4}\) from its centre will be

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Answer & Solution

Correct Answer

(A) \(\frac{{4{\mu _0}i}}{{\sqrt 5 \pi L}}\)

Step-by-step Solution

Detailed explanation

\(B=\frac{\mu_{0} i}{4 \pi R}\left(\sin \theta_{1}+\sin \theta_{2}\right)\)

\(\sin \theta_{2}=\frac{L / 2}{\sqrt{(L / 2)^{2}+(L / 2)^{2}}}=\frac{1}{2(\sqrt{1 / 4+1 / 16})}=\frac{2}{\sqrt{5}}\)

\(\Rightarrow B=\frac{\mu_{0} i}{{4 \pi \frac{L}{4}}}\left(\frac{2 \times 4}{2 \sqrt{5}}\right) B=\frac{4 \mu_{0} i}{\sqrt{5} \pi L}\)

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