JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The dimension of \(\frac{\mathrm{B}^{2}}{2 \mu_{0}}\), where \(\mathrm{B}\) is magnetic field and \(\mu_{0}\) is the magnetic permeability of vacuum, is
- A \(M L^{-1} T^{-2}\)
- B \(\mathrm{ML}^{2} \mathrm{T}^{-1}\)
- C \(\mathrm{ML} \mathrm{T}^{-2}\)
- D \(\mathrm{ML}^{2} \mathrm{T}^{-2}\)
Answer & Solution
Correct Answer
(A) \(M L^{-1} T^{-2}\)
Step-by-step Solution
Detailed explanation
Magnetic energy stored per unit volume is \(\frac{\mathrm{B}^{2}}{2 \mu_{0}}\) Dimension is \(ML ^{-1} \mathrm{T}^{-2}\)
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