ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Kinetic theory of gases
  • JEE Mains 2022
  • Medium
  • Numerical

A vessel contains \(14\,g\) of nitrogen gas at a temperature of \(27^{\circ}\,C\). The amount of heat to be transferred to the gap to double the r.m.s. speed of its molecules will be \(......J\) \(\left(\right.\) Take \(R =8.32\,J\,mol ^{-1} k ^{-1}\) )

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(9360\)

Step-by-step Solution

Detailed explanation

\(v _{ rms } \propto \sqrt{ T }\)

\(v _{ rms } \propto \sqrt{300\,K }, v _{ rms _{ f }}=2 v _{ rms _{ i }}\)

\(v _{ rms _{ f }} \propto \sqrt{1200\,K }\)

\(T _{ f }=1200\,K , T _{ i }=300 K , n =\frac{14}{28}=\frac{1}{2}\)

\(Q = nC _{ v } \Delta T =\frac{1}{2} \times \frac{5 R }{2} \times 900\)

\(Q =9360\,J\)

From JEE Mains
Explore more questions on app