JEE Mains · Physics · STD 11 - 7. gravitation
India's Mangalyan was sent to the Mars by launching it into a transfer orbit \(EOM\) around the sun . It leaves the earth at \(E\) and meets Mars at \(M\) . If the semi-major axis of Earth's orbit is \(a_e = 1.5 \times 10^{11}\, m\), that of Mars orbit \(a_m= 2.28 \times 10^{11}\, m\), taken Kepler's laws give the estimate of time for Mangalyan to reach Mars from Earth to be close to ........ \(days\).
- A \(500\)
- B \(320\)
- C \(260\)
- D \(220\)
Answer & Solution
Correct Answer
(C) \(260\)
Step-by-step Solution
Detailed explanation
semi major axis of mangalyan \({a_{Mn}} = \frac{{{a_c} + {a_m}}}{2}\) \( = 1.89 \times {10^{11}}m\) From kepler's law \({T^2} \propto {R^3}\) \(\therefore \,{\left( {\frac{{{T_{mn}}}}{{Te}}} \right)^2} = {\left( {\frac{{{R_M}}}{{{\operatorname{R} _e}}}} \right)^3}\)…
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