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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

Let \(y=x\) be the equation of a chord of the circle \(C_{1}\) (in the closed half-plane \(x\ge0)\) of diameter 10 passing through the origin. Let \(C_{2}\) be another circle described on the given chord as its diameter. If the equation of the chord of the circle \(C_{2}\), which passes through the point (2, 3) and is farthest from the center of \(C_{2}\), is \(x+ay+b=0,\) then \(a-b\) is equal to:

  1. A 10
  2. B -6
  3. C -2
  4. D 6
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Answer & Solution

Correct Answer

(C) -2

Step-by-step Solution

Detailed explanation

Equation of circle \(C_{2}\) is \(x^{2}+y^{2}-5x-5y=0\) its centre is \((\frac{5}{2},\frac{5}{2})\) \(m_{AB}=-1\) \(\therefore\) Slope of required chord \(=1\) \(\therefore\) equation of required chord is \(x - y + 1 =0\) \(\therefore a =-1, b=2\) \(\therefore a - b =-2\)
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