JEE Mains · Physics · STD 12 -7. Alternating current
As per the given graph choose the correct representation for curve \(A\) and curve \(B\).Where \(X _{ C }=\) reactance of pure capacitive circuit connected with \(A.C.\) source \(X _{ L }=\) reactance of pure inductive circuit connected with \(A.C.\) source \(R =\) impedance of pure resistive circuit connected with \(A.C.\) source \(Z =\) Impedance of the LCR series circuit \(\}\)
- A \(A = X _{ C }, B = R\)
- B \(A = X _{ L }, B = Z\)
- C \(A = X _{ C }, B = X _{ L }\)
- D \(A = X _{ L }, B = R\)
Answer & Solution
Correct Answer
(C) \(A = X _{ C }, B = X _{ L }\)
Step-by-step Solution
Detailed explanation
\(X _{ C }=\frac{1}{\omega C }=\frac{1}{(2 \pi f ) C }\) \(\therefore X _{ C } \propto \frac{1}{ f }\) \(\therefore \text { Curve } A\) \(X _{ L }=\omega L =(2 \pi f ) L\) \(\therefore X _{ L } \propto f\) \(\therefore \text { Curve B }\)
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