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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2023
  • Medium
  • MCQ

As per the given graph choose the correct representation for curve \(A\) and curve \(B\).Where \(X _{ C }=\) reactance of pure capacitive circuit connected with \(A.C.\) source \(X _{ L }=\) reactance of pure inductive circuit connected with \(A.C.\) source \(R =\) impedance of pure resistive circuit connected with \(A.C.\) source \(Z =\) Impedance of the LCR series circuit \(\}\)

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Answer & Solution

Correct Answer

(C) \(A = X _{ C }, B = X _{ L }\)

Step-by-step Solution

Detailed explanation

\(X _{ C }=\frac{1}{\omega C }=\frac{1}{(2 \pi f ) C }\)

\(\therefore X _{ C } \propto \frac{1}{ f }\)

\(\therefore \text { Curve } A\)

\(X _{ L }=\omega L =(2 \pi f ) L\)

\(\therefore X _{ L } \propto f\)

\(\therefore \text { Curve B }\)

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