JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2022
- Hard
- MCQ
A ball is released from a height \(h\). If \(t_{1}\) and \(t_{2}\) be the time required to complete first half and second half of the distance respectively. Then, choose the correct relation between \(t_{1}\) and \(t_{2}\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(t _{2}=(\sqrt{2}-1) t _{1}\)
Step-by-step Solution
Detailed explanation
For first \(\frac{ h }{2}\)
\(\frac{ h }{2}=\frac{1}{2} gt _{1}^{2}\)
For total height \(h\)
\(h =\frac{1}{2} g \left( t _{1}+ t _{2}\right)^{2}\)
\(\frac{1}{\sqrt{2}}=\frac{ t _{1}}{ t _{1}+ t _{2}}\)
\(1+\frac{ t _{2}}{ t _{1}}=\sqrt{2}\)
\(\frac{ t _{1}}{ t _{2}}=\frac{1}{\sqrt{2}-1}\)
\(t _{2}=(\sqrt{2}-1) t _{1}\)
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