JEE Mains · Physics · STD 11 - 2. motion in straight line
A ball is released from a height \(h\). If \(t_{1}\) and \(t_{2}\) be the time required to complete first half and second half of the distance respectively. Then, choose the correct relation between \(t_{1}\) and \(t_{2}\).
- A \(t _{1}=(\sqrt{2}) t _{2}\)
- B \(t _{1}=(\sqrt{2}-1) t _{2}\)
- C \(t _{2}=(\sqrt{2}+1) t _{1}\)
- D \(t _{2}=(\sqrt{2}-1) t _{1}\)
Answer & Solution
Correct Answer
(D) \(t _{2}=(\sqrt{2}-1) t _{1}\)
Step-by-step Solution
Detailed explanation
For first \(\frac{ h }{2}\) \(\frac{ h }{2}=\frac{1}{2} gt _{1}^{2}\) For total height \(h\) \(h =\frac{1}{2} g \left( t _{1}+ t _{2}\right)^{2}\) \(\frac{1}{\sqrt{2}}=\frac{ t _{1}}{ t _{1}+ t _{2}}\) \(1+\frac{ t _{2}}{ t _{1}}=\sqrt{2}\)…
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