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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2016
  • Hard
  • MCQ

Three capacitors each of \(4\,\,\mu F\)  are to be connected in such a way that the effective capacitance is \(6\,\,\mu F.\)  This can be done by connecting thern

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Answer & Solution

Correct Answer

(D) two in series and one in parallel

Step-by-step Solution

Detailed explanation

To get effective capacitance of \(6\,\mu F\) two capacitors of \(4\, \mu \mathrm{F}\) each connected in series and one of \(4\, \mu \mathrm{F}\) capacitor in parallel with them.

Two capacitances in series

\(\therefore \frac{1}{C}=\frac{1}{C_{1}}+\frac{1}{C_{2}}=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}\)

\(1\) capacitor in parallel

\(\therefore \) \(C_{\mathrm{eq}}=C_{3}+C=4+2=6\, \mu \mathrm{F}\)

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