JEE Mains · Physics · STD 11 - 14. waves and sound
Two waves are simultaneously passing through a string and their equations are : \({y}_{1}={A}_{1} \sin {k}({x}-v {t}), {y}_{2}={A}_{2} \sin {k}\left({x}-{vt}+{x}_{0}\right) .\) Given amplitudes \({A}_{1}=12\, {mm}\) and \({A}_{2}=5\, {mm}\) \({x}_{0}=3.5\, {cm}\) and wave number \({k}=6.28\, {cm}^{-1}\). The amplitude of resulting wave will be \(......\,{mm}\)
- A \(7\)
- B \(10\)
- C \(25\)
- D \(49\)
Answer & Solution
Correct Answer
(A) \(7\)
Step-by-step Solution
Detailed explanation
\({y}_{1}={A}_{1} \operatorname{sink}({x}-{vt})\) \({y}_{1}=12 \sin 6.28({x}-{vt})\) \({y}_{2}=5 \sin 6.28({x}-{vt}+3.5)\) \(\Delta \phi=\frac{2 \pi}{\lambda}(\Delta {x})\) \(={K}(\Delta {x})\) \(=6.28 \times 3.5=\frac{7}{2} \times 2 \pi=7 \pi\)…
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