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JEE Mains · Physics · STD 11 - 13. oscillations

The velocity of a particle executing simple harmonic motion along \(x\)-axis is described as \(v^2 = 50 - x^2\), where \(x\) represents displacement. If the time period of motion is \(\dfrac{x}{7}\) s, the value of \(x\) is _____.

  1. A 40
  2. B 44
  3. C 48
  4. D 52
Verified Solution

Answer & Solution

Correct Answer

(B) 44

Step-by-step Solution

Detailed explanation

The given equation is \(v^2 = 50 - x^2\) Differentiating with respect to \(x\): \(2v \dfrac{dv}{dx} = -2x\) \(v \dfrac{dv}{dx} = -x\) Since acceleration \(a = v \dfrac{dv}{dx}\), we get: \(a = -x\) Comparing this with the standard equation of SHM \(a = -\omega^2 x\), we get:…
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