JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The variation of stopping potential \(\left(V_0\right)\) as a function of the frequency \(\nu \left(\times 10^{14} Hz\right).\) of the incident light for a metal is shown in figure. The work function of the surface is \(...........\,eV\)
- A \(18.6\)
- B \(2.98\)
- C \(2.07\)
- D \(1.36\)
Answer & Solution
Correct Answer
(C) \(2.07\)
Step-by-step Solution
Detailed explanation
\(eV _0= h v-\phi\) \(0= h v-\phi\) \(\phi= h v\) \(=6.6 \times 10^{-34} \times 5 \times 10^{14}\) \(=33 \times 10^{-20}\,J\) \(\phi=\frac{33 \times 10^{-20}}{1.6 \times 10^{-19}}=2.07\,eV\)
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