JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2023
- Medium
- MCQ
The variation of stopping potential \(\left(V_0\right)\) as a function of the frequency \(\nu \left(\times 10^{14} Hz\right).\) of the incident light for a metal is shown in figure. The work function of the surface is \(...........\,eV\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(2.07\)
Step-by-step Solution
Detailed explanation
\(eV _0= h v-\phi\)
\(0= h v-\phi\)
\(\phi= h v\)
\(=6.6 \times 10^{-34} \times 5 \times 10^{14}\)
\(=33 \times 10^{-20}\,J\)
\(\phi=\frac{33 \times 10^{-20}}{1.6 \times 10^{-19}}=2.07\,eV\)
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