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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2023
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  • MCQ

The variation of stopping potential \(\left(V_0\right)\) as a function of the frequency \(\nu \left(\times 10^{14} Hz\right).\) of the incident light for a metal is shown in figure. The work function of the surface is \(...........\,eV\)

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Answer & Solution

Correct Answer

(C) \(2.07\)

Step-by-step Solution

Detailed explanation

\(eV _0= h v-\phi\)

\(0= h v-\phi\)

\(\phi= h v\)

\(=6.6 \times 10^{-34} \times 5 \times 10^{14}\)

\(=33 \times 10^{-20}\,J\)

\(\phi=\frac{33 \times 10^{-20}}{1.6 \times 10^{-19}}=2.07\,eV\)

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