JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2019
- Medium
- MCQ
The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea \((7.8\, mm)\). This surface separates two media of refractive indices \(1\) and \(1.34\). Calculate the distance from the refracting surface at which a parallel beam of light will come to focus.......\(cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(3.1\)
Step-by-step Solution
Detailed explanation
\({\frac{\mu_{2}}{\mathrm{v}}-\frac{\mu_{1}}{\mathrm{u}}=\frac{\mu_{2}-\mu_{1}}{\mathrm{R}}}\)
\({\Rightarrow \quad \frac{1.34}{\mathrm{v}}-\frac{1}{-\infty}=\frac{0.34}{7.8}} \)
\( \Rightarrow {\text{v}} = \frac{{1.34 \times 7.8}}{{0.34}}\,\,{\text{nm}}\) \( = 3.074\,{\text{cm}}\)
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