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JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments

The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea \((7.8\, mm)\). This surface separates two media of refractive indices \(1\) and \(1.34\). Calculate the distance from the refracting surface at which a parallel beam of light will come to focus.......\(cm\)

  1. A \(1\)
  2. B \(2\)
  3. C \(4\)
  4. D \(3.1\)
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Answer & Solution

Correct Answer

(D) \(3.1\)

Step-by-step Solution

Detailed explanation

\({\frac{\mu_{2}}{\mathrm{v}}-\frac{\mu_{1}}{\mathrm{u}}=\frac{\mu_{2}-\mu_{1}}{\mathrm{R}}}\) \({\Rightarrow \quad \frac{1.34}{\mathrm{v}}-\frac{1}{-\infty}=\frac{0.34}{7.8}} \) \( \Rightarrow {\text{v}} = \frac{{1.34 \times 7.8}}{{0.34}}\,\,{\text{nm}}\)…
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