JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2014
- Hard
- MCQ
A Zener diode is connected to a battery and a load as show below: The currents, \(I, I_Z\) and \(I_L\) are respectively .

Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(12.5\,mA, 7.5\,mA, 5\, mA\)
Step-by-step Solution
Detailed explanation
Here, \(R=4 \mathrm{k} \Omega=4 \times 10^{3} \Omega\)
\(V_{i}=60 \mathrm{V}\)
Zener voltage \(V_{z}=10 \mathrm{V}\) \(R_{L}=2 \mathrm{k} \Omega=2 \times 10^{3} \Omega\)
Load current, \(I_{\mathrm{L}}=\frac{V_{Z}}{R_{L}}=\frac{10}{2 \times 10^{3}}=5 \mathrm{\,mA}\)
Current through \(R, I=\frac{V_{i}-V_{Z}}{R}\)
\(=\frac{60-10}{4 \times 10^{3}}=\frac{50}{4 \times 10^{3}}=12.5 \mathrm{\,mA}\)
Fom circuit diagram,
\(I=I_{z}+I_{L}\)
\(\Rightarrow 12.5=I_{z}+5\)
\(\Rightarrow I_Z\,=\,12.5-5\,=\,7.5\,mA\)
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