ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2021
  • Hard
  • Numerical

\(27\) similar drops of mercury are maintained at \(10 \,V\) each. All these spherical drops combine into a single big drop. The potential energy of the bigger drop is ....... times that of a smaller drop.

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(243\)

Step-by-step Solution

Detailed explanation

\((27)\left(\frac{4}{3} \pi r ^{3}\right)=\frac{4}{3} \pi R ^{3}\)

\(R =3 r\)

Potential energy of smaller drop :

\(U _{1}=\frac{3}{5} \frac{ kq ^{2}}{ r }\)

Potential energy of bigger drop :

\(U =\frac{3}{5} \frac{ kQ ^{2}}{ R }\)

\(U =\frac{3}{5} \frac{ k (27 q )^{2}}{ R }\)

\(U =\frac{3}{5} k \frac{(27)(27) q ^{2}}{3 r }\)

\(U =\frac{(27)(27)}{3}\left(\frac{3}{5} \frac{ kq ^{2}}{ r }\right)\)

\(U =243 U _{1}\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app