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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2026
  • Medium
  • MCQ

A convex lens is made from glass material having refractive index of \(1.4\) with same radius of curvature on both sides. The ratio of its focal length and radius of curvature is ______.

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Answer & Solution

Correct Answer

(D) \(1.25\)

Step-by-step Solution

Detailed explanation

Using the lens maker's formula:

\(\dfrac{1}{f} = (\mu - 1) \left( \dfrac{1}{R_1} - \dfrac{1}{R_2} \right)\)

For an equiconvex lens, \(R_1 = R\) and \(R_2 = -R\). Given \(\mu = 1.4\):

\(\dfrac{1}{f} = (1.4 - 1) \left( \dfrac{1}{R} - \dfrac{1}{-R} \right)\)

\(\dfrac{1}{f} = 0.4 \times \dfrac{2}{R}\)

\(\dfrac{1}{f} = \dfrac{0.8}{R}\)

\(\dfrac{f}{R} = \dfrac{1}{0.8} = 1.25\)

Answer: \(1.25\)
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