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JEE Mains · Physics · STD 12 - Current electricity
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Sliding contact of a potentiometer is in the middle of the potentiometer wire having resistance \(R_p=1 \Omega\) as shown in the figure. An external resistance of \(R_e=2 \Omega\) is connected via the sliding contact. The electric current in the circuit is :

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Answer & Solution

Correct Answer

(D) 1.0 A

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Detailed explanation

The circuit can be considered as

\(\begin{aligned} & \therefore \mathrm{R}_{\text {eq }}=0.5+\frac{0.5 \times 2}{2+0.5}=\left(\frac{5}{10}+\frac{10}{25}\right) \Omega \\ & =\frac{45}{50}=\frac{9}{10}=0.9 \\ & \therefore \mathrm{i}=\frac{0.9}{0.9}=1 \mathrm{~A}\end{aligned}\)
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