JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
Three blocks \(\mathrm{M}_1, \mathrm{M}_2, \mathrm{M}_3\) having masses \(4 \mathrm{~kg}, 6 \mathrm{~kg}\) and \(10 \mathrm{~kg}\) respectively are hanging from a smooth pully using rope 1,2 and 3 as shown in figure. The tension in the rope \(1, \mathrm{~T}_1\) when they are moving upward with acceleration of \(2 \mathrm{~ms}^{-2}\) is _______ \(\mathrm{N}\) (if \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\) )

- A \(210\)
- B \(220\)
- C \(230\)
- D \(240\)
Answer & Solution
Correct Answer
(D) \(240\)
Step-by-step Solution
Detailed explanation
\(FBD\) of \(M_1\) : \(\mathrm{T}_1-200=(4+6+10) \times 2\) \(\therefore \mathrm{T}_1=240\)
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