A plane electromagnetic wave of wavelength λ has an intensity I. It is propagating along the positive Y- direction. The allowed expressions for the electric and magnetic fields are given by

(C) \vec E\, = \,\sqrt {\frac{{2I}}{{{\varepsilon _0}C}}} \cos \left[ {\frac{{2\pi }}{\lambda }(y - ct)} \right]\,\hat k\,;\,\vec B\, = + \frac{1}{c}E\hat i

(A) \vec E\, = \,\sqrt {\frac{I}{{{\varepsilon _0}C}}} \cos \left[ {\frac{{2\pi }}{\lambda }(y - ct)} \right]\,\hat i\,;\,\vec B\, = \,\frac{1}{c}E\hat k

(B) \vec E\, = \,\sqrt {\frac{I}{{{\varepsilon _0}C}}} \cos \left[ {\frac{{2\pi }}{\lambda }(y - ct)} \right]\,\hat k\,;\,\vec B\, = - \,\frac{1}{c}E\hat i

(C) \vec E\, = \,\sqrt {\frac{{2I}}{{{\varepsilon _0}C}}} \cos \left[ {\frac{{2\pi }}{\lambda }(y - ct)} \right]\,\hat k\,;\,\vec B\, = + \frac{1}{c}E\hat i

(D) \vec E\, = \,\sqrt {\frac{{2I}}{{{\varepsilon _0}C}}} \cos \left[ {\frac{{2\pi }}{\lambda }(y + ct)} \right]\,\hat k\,;\,\vec B\, = \frac{1}{c}E\hat i

A plane electromagnetic wave of… | JEE Mains Physics 2018

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\(II\) Wavelength corresponding to temperature associated with the isotropic radiation filling all space	\((B)\) Microwave
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A plane electromagnetic wave of wavelength \(\lambda \) has an intensity \(I.\) It is propagating along the positive \(Y-\) direction. The allowed expressions for the electric and magnetic fields are given by

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