JEE Mains · Physics · STD 12 - 12. atoms
The ratio of wavelength of spectral lines \(H_\alpha\) and \(H _\beta\) in the Balmer series is \(\frac{x}{20}\). The value of \(x\) is \(...............\)
- A \(27\)
- B \(26\)
- C \(25\)
- D \(24\)
Answer & Solution
Correct Answer
(A) \(27\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{\lambda}= R \left[\frac{1}{ n _1{ }^2}-\frac{1}{ n _2{ }^2}\right]\) for \(H\)-atom For balmer series, \(n _1=2\) \(\frac{1}{\lambda}= R \left[\frac{1}{4}-\frac{1}{ n _2^2}\right]\) For \(H _{ i }, n _2=3\) \(H _\beta, n _2=4\)…
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