JEE Mains · Physics · STD 12 - 12. atoms
The radius of fifth orbit of the \(L ^{++}\)is \(.........\times 10^{-12}\,m\). Take : radius of hydrogen atom \(=0.51 \mathring A\)
- A \(424\)
- B \(423\)
- C \(422\)
- D \(425\)
Answer & Solution
Correct Answer
(D) \(425\)
Step-by-step Solution
Detailed explanation
\(r _{ n }= r _0 \frac{ n ^2}{ z } \rightarrow r _{ n }=0.51 \times \frac{25}{3} \mathring A=4.25 \times 10^{-10}\,m\) \(=425 \times 10^{-12}\,m\)
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