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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2023
  • Medium
  • Numerical

A capacitor of capacitance \(150.0\,\mu F\) is connected to an alternating source of \(emf\) given by \(E =36\) \(\sin (120 \pi t ) V\). The maximum value of current in the circuit is approximately equal to \(......\,A\)

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Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

\(I_0=\frac{E_0}{x_c}=\frac{E_0}{\frac{1}{\omega_c}}=E_0 \omega_c\)

\(\Rightarrow I_0=36 \times 120 \pi \times 150 \times 10^{-6}\)

\(\Rightarrow I_0=2.03\)

\(\simeq 2\,A\)

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