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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2021
  • Medium
  • Numerical

The radius in kilometer to which the present radius of earth \(( R =6400\, km )\) to be compressed so that the escape velocity is increased \(10\) time is ............\(km\)

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Correct Answer

(A) \(64\)

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Detailed explanation

\(V _{ e }=\sqrt{\frac{2 Gm }{ R }}\)

\(10 V _{ e }=\sqrt{\frac{2 Gm }{ R ^{\prime}}}\)

\(\therefore 10=\sqrt{\frac{ R }{ R ^{\prime}}}\)

\(\Rightarrow R ^{\prime}=\frac{ R }{100}=\frac{6400}{100}=64 km\)

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