JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
Given below is the plot of a potential energy function \(U(x)\) for a system, in which a particle is in one dimensional motion, while a conservative force \(F(x)\) acts on it. Suppose that \(E_{\text {mech }}=8\, {J}\), the incorrect statement for this system is:
- A at \(x=x_{3}\), \(K.E.=4\;J\)
- B at \(x=x_{2}\), \(K.E.\) is greatest and the particle is moving at the fastest speed.
- C at \(x\,<\,x_{1}\), \(K.E.\) is smallest and the particle is moving at the slowed speed.
- D at \(x\,>\,x_{4}\), \(K.E.\) is constant throughout the region.
Answer & Solution
Correct Answer
(C) at \(x\,<\,x_{1}\), \(K.E.\) is smallest and the particle is moving at the slowed speed.
Step-by-step Solution
Detailed explanation
Given \(\left.E_{\text {mech. }}=8\right]\) \((A)\) at \(x\,>\,x_{4}, \quad U=\) constant \(\left.=6\right]\) \({K}={E}_{{mech} .}-{U}=2\, {J}=\) constant \((B)\) at \(x\,<\,x_{1}, \quad U=\) constant \(\left.=8\right]\) \({K}={E}_{\text {mech. }}-{U}=8-8=0 \,{J}\) Particle is…
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